The figure shows a relation from set A to set B.
The range of the relation is:
{a, b, c, d}
{1, 2, 3, 4, 5}
{ (a,1), (b,1), (c,4), (d,2) }
{1, 2, 4}
Given the function f:x → 3x + 1 and g: 2x, fg(x) is:
6x² + 1.
6x.
6x+2.
6x + 1.
Given the function f: x ⟼ 2x − 1 the value of f(-3) is:
-5.
5.
-7.
7.
For any function f, f⁻¹ always maps its:
Range to its domain.
Image to the range.
Domain to its codomain.
Domain to its range.
The figure is a quadratic graph of y = f(x).
The solution of f(x) = 0 is/are:
1 and -3.
1.
-1 and 3.
3.
