Two functions f·g: ℝ → ℝ are such that
f(x) = 2x - 1 and (f·g)(x) = x - 2.
Then g(x) is:
(x+1) / 2.
(x-1) / 2.
(x-2) / 2.
(2x-1) / 2.
Given the functions f·g: ℝ → ℝ, where f(x) = x² - 1 and g(x) = 2x + 1.
(g·f)(2) is:
24.
7.
11.
13.