0.000 s
Revise smart, understand Better
Select Lessons (14)
Acid-Base Equilibrium
Atomic Structure And Related Patterns In The Periodic Table
Bonding And Structure, And Intermolecular Forces
Chemical Equilibrium
D-Block Elements (Transition Elements)
DESCRIPTIVE INORGANIC CHEMISTRY: Group IV (14)
DESCRIPTIVE INORGANIC CHEMISTRY: Halogens (GROUP VII or 17)
DESCRIPTIVE INORGANIC CHEMISTRY: Modern Periodic Table, Periodicity And S-Block Elements
Functional Group Chemistry And Reaction Mechanism
ORGANIC CHEMISTRY: Fundamentals
Raoult’s Law And Phase Equilibria
Reaction Kinetics
Redox Equilibrium
The Mole Concept
5/30 MCQs for:
Raoult’s Law And Phase Equilibria
If two liquids A and B form minimum boiling azeotrope at some specific composition then.
Vapour pressure of solution decreases because less number of molecules of only one of the liquids escape from the solution.
A–B interactions are stronger than those between A–A or B–B.
Vapour pressure of solution remains the same because more number of molecules of liquids A and B can escape from the solution.
A–B interactions are weaker than those between A–A or B–B.
Liquids that dissolve in each other in all proportions to form a homogeneous mixture at a specific temperature are known as:
Soluble liquids.
Miscible liquids.
Real liquids.
Ideal liquids.
On the basis of information given below mark the correct option. On adding acetone to methanol some of the hydrogen bonds between methanol molecules break.
Specific composition methanol¬-acetone mixture forms maximum boiling azeotrope and will show positive deviation from Raoult’s law.
At specific composition methanol¬-acetone mixture will form minimum boiling azeotrope and will show negative deviation from Raoult’s law.
At specific composition methanol¬-acetone mixture will form maximum boiling azeotrope and will show negative deviation from Raoult’s law.
At specific composition methanol¬-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult’s law.
Hexane and heptane form an ideal mixture. The vapour pressures of pure hexane and heptane at 298 K are 19 kPa and 36 kPa respectively. Calculate the total vapour pressure of the solution that contains 0.978 mole of hexane and 0.364 mole of heptane.
33.37 kPa.
13.85 kPa.
9.76 kPa.
23.61 kPa.
Which of the following pairs of liquids when mixed would give a higher boiling point that predicted by Raoult’s law?
Nitric acid and water.
Propanol and ethanol.
Propane and trichloromethane.
Hexane and water.