Given the function, f(x) = 1 - 2x. The value of f(-3) is:
-5.
7.
-7.
5.
Given the function f defined over R by f:x → 2x² - 3.
The value of f(-2) is:
-11
-7
-5
5
Given the mapping in the figure, the range set is:
{1, 2, 3, 4}
{2, 5, 8}.
{1, 2, 5, 5, 8}
{2, 3, 5}
The figure is a quadratic graph of y = f(x).
The solution of f(x) = 0 is/are:
1 and -3.
1.
-1 and 3.
3.
For any function f, f⁻¹ always maps its:
Domain to its codomain.
Domain to its range.
Range to its domain.
Image to the range.
